2x^2-144x-1295=0

Solution for 2x^2-144x-1295=0 equation:

2x^2-144x-1295=0

a = 2; b = -144; c = -1295;
Δ = b2-4ac
Δ = -1442-4·2·(-1295)
Δ = 31096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{31096}=\sqrt{676*46}=\sqrt{676}*\sqrt{46}=26\sqrt{46}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-144)-26\sqrt{46}}{2*2}=\frac{144-26\sqrt{46}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-144)+26\sqrt{46}}{2*2}=\frac{144+26\sqrt{46}}{4}
$